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Optimal pot

25.4.1
Optimal pot
Fig. 1
Optimal pot with base without lid
d* Optimum diameter h* Optimum height A* Optimum area
Eqn. 1
\require{color}\definecolor{myred}{RGB}{255,0,0} d^\ast=\sqrt[3]{\frac{8\cdot Vol}{\mathrm\pi}}
Eqn. 2
\require{color}\definecolor{myred}{RGB}{255,0,0} h=\frac{4\cdot V}{d^{\color{myred}2}\cdot\pi}
Eqn. 3
\require{color}\definecolor{myred}{RGB}{255,0,0} A=d^{\color{myred}2}\cdot\frac\pi4+d\cdot\pi\cdot h
Eqn. 4
\require{color}\definecolor{myred}{RGB}{255,0,0} q=\frac{A^\ast}{A_{\color{myred}ref}}-1
Optimal diameterd*=108.4mm 
Optimal heighth*=54.19mm 
Optimal areaA*=27,679.1mm2 
Heighthref=99.47mm 
SurfaceAref=30,026.5mm2 
Percent lossq=-7.8% 
VolumeVol = 0.5L
Diameterdref = 80mm
Calc 1
Optimal pot

Example 1 An optimal coffee cup with a beverage content of 0.5 l has an optimal diameter of 108 mm with a cup height of 54 mm. If the cup diameter of a reference cup is 80 mm instead, this results in a cup height of 99 mm with the same volume. The excess area consumption (loss q) of the reference cup is -7.8%.

Example 2 A cooking pot with a capacity of 5.75 l has an optimal diameter of 244 mm and a height of 122 mm. If the reference diameter is instead 200 mm, this results in a height of 183 mm with the same volume. The excess land use (loss q) of the reference pot is -3.7%.

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