Yield Stress According to Ludwik

1.3.1
Eqn. 1
\require{color}\definecolor{myred}{RGB}{255,0,0} k_{\color{myred}f}=C\cdot\varphi^{\color{myred}n}
Yield stresskf=349.78MPa 
Strain hardening constantC = 500MPa
Natural strainφ = 0.2
Strain hardening exponentn = 0.22
Calc 1
Yield stress according to Ludwik-Hollomon1011

For unalloyed and low-alloy steels, the yield stress depends on the material in question. In addition, it is influenced by the condition, the pre-treatment, the natural strain, the deformation speed and the deformation temperature.

A low yield stress reduces the restoring moment caused by springback effects and thus leads to better shape retention.

Eqn. 2
\require{color}\definecolor{myred}{RGB}{255,0,0} C=R_{\color{myred}m}\cdot\left(\frac en\right)^{\color{myred}n}=R_{\color{myred}m}\cdot\left(\frac{2,72}n\right)^{\color{myred}n}
Eqn. 3
\require{color}\definecolor{myred}{RGB}{255,0,0} n\approx\varphi_{\color{myred}gl}=ln(1+A_{\color{myred}gl})
Strain hardening constantC=541MPa 
Tensile strengthRm = 313MPa
Strain hardening exponentn = 0.22
Calc 2
Strain hardening constant C & strain hardening exponent n1011

The material-specific constant C can be approximately estimated using the tensile strength and uniform elongation from the tensile test.

A disadvantage of the Ludwik equation is the infinite slope e at φ0. The Swift approach offers an improvement.

The Ludwik equation is valid for natural strains ≤ 1 and room temperature, but is not suitable for high-alloy steels and copper.

The following applies to cold-formed steel and Al alloys in the range of φ = 0.2... 1:

In a double logarithmic network, the flow curves can be approximated by a straight line with the slope n (from the material table).

10
Birkert, A. et al.Umformtechnische Herstellung komplexer KarosserieteileSpringer ViewegBerlin - Heidelberg2013
11
Doege, E. et. al.Fließkurvenatlas metallischer WerkstoffeHanser VerlagMünchen1986
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